If a projectile is shot at an angle of #pi/3# and at a velocity of #26 m/s#, when will it reach its maximum height??

1 Answer
Dec 28, 2016

Answer:

#t=2.3# seconds rounded to 1 decimal place

Explanation:

The maximum height is when the vertical velocity component of the projectile is equal to the vertically downward velocity due to gravity.

Tony B

Thus we have the model:

#=> Rsin(theta)="g"t#

Where
#R= 26m/s#
#theta=pi/3#
#g~~9.81 m/s^2 larr" known"#

#t# is time in seconds

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

This becomes:

#=>26color(red)(m/s)sin(pi/3)=9.81color(red)(m/s^2)color(white)(.)t#

You manipulate the units in the same way you do the numbers

#=>t= 26/9.81 sin(pi/3)color(red)( xx(cancel(m))/(cancel(s))xxs^(cancel(color(white)(.)2))/(cancel(m)) larr" dealing with the units")#

#t=2.29527...# seconds

#t=2.3# seconds rounded to 1 decimal place