# If a projectile is shot at an angle of pi/3 and at a velocity of 29 m/s, when will it reach its maximum height??

May 2, 2016

$t = 2 , 56 \text{ } s$

#### Explanation:

alpha=pi/3" sin (pi/3)=0,866
$\text{initial velocity :"v_i=29 " } \frac{m}{s}$

$\text{it has "v_y=0"; if object reaches its maximum height.}$

${v}_{y} = {v}_{i} \cdot \sin \alpha - g \cdot t$

$0 = {v}_{i} \cdot \sin \alpha - g \cdot t$

$t = \frac{{v}_{i} \cdot \sin \alpha}{g} \text{ elapsed time to the maximum height}$

$t = \frac{29 \cdot 0 , 866}{9 , 81}$

$t = 2 , 56 \text{ } s$