Question

If a projectile is shot at an angle of `pi/3` and at a velocity of `36 m/s`, when will it reach its maximum height??

Answer 1

`"3.18 s"`

Explanation:

Time to reach maximum height is

`"T" = ("u" sinα)/"g"`

`"T" = ("36 m/s" × sin(π/3))/"9.8 m/s"^2 = "3.18 s"`