# If a projectile is shot at an angle of pi/3 and at a velocity of 36 m/s, when will it reach its maximum height??

$\text{3.18 s}$
$\text{T" = ("u" sinα)/"g}$
$\text{T" = ("36 m/s" × sin(π/3))/"9.8 m/s"^2 = "3.18 s}$