If a projectile is shot at an angle of #pi/4# and at a velocity of #12 m/s#, when will it reach its maximum height??

1 Answer
Apr 3, 2018

Answer:

The time is #=0.87s#

Explanation:

Resolving in the vertical direction #uarr^+#

The initial velocity is #u_0=(12)sin(1/4pi)ms^-1#

The acceleration due to gravity is #a=-g=-9.8ms^-2#

The time to reach the greatest height is #=ts#

At the maximum height #v=0ms^-1#

Applying the equation of motion

#v=u+at=u- g t #

The time is #t=(v-u)/(-g)=(0-(12)sin(1/4pi))/(-9.8)=0.87s#