Question

If a projectile is shot at an angle of `pi/4` and at a velocity of `32 m/s`, when will it reach its maximum height??

Answer 1

`2.31s`

Explanation:

here,the upward movement of the projectile will be due to the upward component of its velocity i.e `32 sin (pi/4)`

So,we can apply, `v=u-g t` to find the time taken to reach its maximum height.

At,maximum height upward component of velocity is zero,initial upward velocity is `32 sin (pi/4)`

So, `t= (32 sin (pi/4))/g=2.31 s`