If a projectile is shot at an angle of pi/4 and at a velocity of 32 m/s, when will it reach its maximum height??

Mar 2, 2018

$2.31 s$

Explanation:

here,the upward movement of the projectile will be due to the upward component of its velocity i.e $32 \sin \left(\frac{\pi}{4}\right)$

So,we can apply, $v = u - g t$ to find the time taken to reach its maximum height.

At,maximum height upward component of velocity is zero,initial upward velocity is $32 \sin \left(\frac{\pi}{4}\right)$

So, $t = \frac{32 \sin \left(\frac{\pi}{4}\right)}{g} = 2.31 s$