If a projectile is shot at an angle of #(pi)/8# and at a velocity of #14 m/s#, when will it reach its maximum height?

1 Answer
Feb 9, 2016

Answer:

#h_(max)~=1,463 " m"#

Explanation:

#h_(max) " of a projectile may be calculated by:"#
#h_(max)=(v_i^2*sin^2 theta)/(2*g)#
#theta=pi/8 * 180/pi#
#theta=22,5 ^o#
#sin theta=0,382683432365#
#sin^2 theta=0,146446609409#
#h_(max)=(14^2*0,14644609409)/(2*9,81)#
#h_(max)=(196*0,14644609409)/(19,62)#
#h_(max)~=1,463 " m"#