Question

If a projectile is shot at an angle of `(pi)/8` and at a velocity of `14 m/s`, when will it reach its maximum height?

Answer 1

`h_(max)~=1,463 " m"`

Explanation:

`h_(max) " of a projectile may be calculated by:"`
`h_(max)=(v_i^2*sin^2 theta)/(2*g)`
`theta=pi/8 * 180/pi`
`theta=22,5 ^o`
`sin theta=0,382683432365`
`sin^2 theta=0,146446609409`
`h_(max)=(14^2*0,14644609409)/(2*9,81)`
`h_(max)=(196*0,14644609409)/(19,62)`
`h_(max)~=1,463 " m"`