If a projectile is shot vertically from the ground at 1 m/s, how long will it remain in the air?

Apr 29, 2016

$\approx 0.2 s$

Explanation:

Since the projectile is projected vertically then free vertical motion under gravity to be applied.
Here Initial velocity $u = 1 \frac{m}{s}$
If its time of flight be taken as T s, then after Ts it will return to the initial position at the ground ,making a verticalb displacement $h = 0$ Taking acceleration due to gravity $g = 9.8 m {s}^{-} 2$
we can write:
$h = u \times T - \frac{1}{2} \times g \times {T}^{2} \implies 0 = 1 \times T - \frac{1}{2} \times 9.8 \times {T}^{2}$
$\therefore T = \frac{1}{4.9} s \approx 0.2 s$