Question

If a spring has a constant of `12 (kg)/s^2`, how much work will it take to extend the spring by `77 cm`?

Answer 1

The work done is `=3.56J`

Explanation:

The work is equal to the energy stored in the spring

The spring constant is `k=12kgs^-2`

The extension is `x=0.77m`

The energy stored is

`W=1/2kx^2=1/2*12*0.77^2=3.56J`