# If a spring has a constant of 12 (kg)/s^2, how much work will it take to extend the spring by 77 cm ?

Jul 15, 2018

The work done is $= 3.56 J$

#### Explanation:

The work is equal to the energy stored in the spring

The spring constant is $k = 12 k g {s}^{-} 2$

The extension is $x = 0.77 m$

The energy stored is

$W = \frac{1}{2} k {x}^{2} = \frac{1}{2} \cdot 12 \cdot {0.77}^{2} = 3.56 J$