If a spring has a constant of 2 (kg)/s^2, how much work will it take to extend the spring by 44 cm ?

Mar 20, 2018

$\text{0.1936 Joule}$

Explanation:

Potential energy $\left(\text{U}\right)$ gained by spring on stretching is

${\text{U" = 1/2\ "kx}}^{2}$

$\text{U" = 1/2 × "2 kg/s"^2 × ("0.44 m")^2 = "0.1936 Joule}$

From work energy theorem, this equal to the amount of work done on the spring to stretch it by $\text{44 cm}$