Question

If a spring has a constant of `2 (kg)/s^2`, how much work will it take to extend the spring by `87 cm`?

Answer 1

`"0.76 Joule"`

Explanation:

Energy stored in a spring is given by

`U = 1/2\ "kx"^2`

Energy stored in spring when it’s streched by `"87 cm"` is

`U = 1/2\ "kx"^2 = 1/cancel(2)\ cancel(2)\ "kg/s"^2 × ("0.87 m")^2 = "0.76 Joule"`

Work = `U_f - U_i = "0.76 J - 0 J = 0.76 J"`