If a spring has a constant of 4 (kg)/s^2, how much work will it take to extend the spring by 73 cm ?

1 Answer
Mar 24, 2018

1.0658 J

Explanation:

Spring constant, k = 4 (kg)/s^2
Spring initial position, x_i = 0 m
Spring final position, x_f = 0.73 m

Work done by a spring can be found using the equation:
W_(sp) = 1/2k(X_f^2 - X_i^2)

Plug in your values:
W_(sp) = 1/2(4)((0.73)^2 - (0)^2)
W_(sp) =1.0658 J (Don't forget about units)

Hope this helps!