If a spring has a constant of #4 (kg)/s^2#, how much work will it take to extend the spring by #73 cm #?

1 Answer
Mar 24, 2018

Answer:

1.0658 J

Explanation:

Spring constant, #k = 4 (kg)/s^2#
Spring initial position, #x_i = 0 m#
Spring final position, #x_f = 0.73 m#

Work done by a spring can be found using the equation:
#W_(sp) = 1/2k(X_f^2 - X_i^2)#

Plug in your values:
#W_(sp) = 1/2(4)((0.73)^2 - (0)^2)#
#W_(sp) =1.0658 # J (Don't forget about units)

Hope this helps!