# If a spring has a constant of 7 (kg)/s^2, how much work will it take to extend the spring by 52 cm ?

Apr 13, 2017

The work done is $= 0.95 J$

#### Explanation:

The spring constant is $k = 7 k g {s}^{-} 2$

The extension is $x = 0.52 m$

The work done to extend the spring is equal to the potential energy of the spring.

$W = \frac{1}{2} k {x}^{2} = \frac{1}{2} \cdot 7 \cdot {0.52}^{2} = 0.95 J$