# If an object is dropped, how fast will it be moving after 12s?

Apr 16, 2018

The answer is $117.6 \frac{m}{s}$.

#### Explanation:

The standard formula for the final speed of an object that moves with constant acceleration (in this case $g$, the gravitational acceleration) is:

$v = {v}_{0} + g t$

As the initial velocity ${v}_{0}$ is equal to $0$ (as the object is initially at rest), we get (of course without taking air friction into account):

$v = 9.8 \frac{m}{s} ^ 2 \setminus \cdot 12 s = 117.6 \frac{m}{s}$