If an object is dropped, how fast will it be moving after #12s#?

1 Answer
Apr 16, 2018

Answer:

The answer is #117.6m/s#.

Explanation:

The standard formula for the final speed of an object that moves with constant acceleration (in this case #g#, the gravitational acceleration) is:

#v=v_0+g t#

As the initial velocity #v_0# is equal to #0# (as the object is initially at rest), we get (of course without taking air friction into account):

#v=9.8 m/s^2 \cdot 12s=117.6m/s#