If an object is dropped, how fast will it be moving after 12s?

1 Answer
Apr 16, 2018

The answer is 117.6m/s.

Explanation:

The standard formula for the final speed of an object that moves with constant acceleration (in this case g, the gravitational acceleration) is:

v=v_0+g t

As the initial velocity v_0 is equal to 0 (as the object is initially at rest), we get (of course without taking air friction into account):

v=9.8 m/s^2 \cdot 12s=117.6m/s