Question

If an object is dropped, how fast will it be moving after `12s`?

Answer 1

The answer is `117.6m/s`.

Explanation:

The standard formula for the final speed of an object that moves with constant acceleration (in this case `g`, the gravitational acceleration) is:

`v=v_0+g t`

As the initial velocity `v_0` is equal to `0` (as the object is initially at rest), we get (of course without taking air friction into account):

`v=9.8 m/s^2 \cdot 12s=117.6m/s`