# If an object is dropped, how fast will it be moving after 23 s?

Apr 25, 2018

$\text{225.4 m/s}$

#### Explanation:

Use equation of motion

$\text{v = u + at}$

where

• $\text{u =}$ Velocity at $\text{t = 0}$
• $\text{v =}$ Velocity after time $\text{t}$
• $\text{a =}$ Acceleration
• $\text{t =}$ Time at which velocity is $\text{v}$

$\text{v = 0 m/s + (9.8 m/s"^2 × "23 s) = 225.4 m/s}$