If an object is moving at 1 m/s and accelerates to 12 m/s over 3 seconds, what was the object's rate of acceleration?

Dec 19, 2015

$a \approx 4 \text{m/s"^2}$
$a = \frac{{v}_{f} - {v}_{i}}{\Delta t}$, where ${v}_{f} = \text{12 m/s}$, ${v}_{i} = \text{1 m/s}$, $\Delta t = \text{3 s}$.
$a = \left(12 \text{m/s"-1"m/s")/(3"s}\right)$
a=(11"m/s")/(3"s")=11/3 "m/s"^2~~"4 m/s"^2" (rounded to one significant figure)