If an object is moving at #120 m/s# over a surface with a kinetic friction coefficient of #u_k=8 /g#, how far will the object continue to move?

1 Answer
Mar 23, 2016

Answer:

#Delta x=900" m"#

Explanation:

#"Object has a kinetic energy due to motion"#
#"The kinetic energy of object is changed to heat energy by"#
#"the friction force"#
#F_f=mu*m*g" "mu=8/g#
#F_f=8/cancel(g)*m*cancel(g)#

#1/2*m*v^2=F_f*Delta x#
#1/2 *cancel(m)*v^2=8*cancel(m) *Delta x#
#1/2*120^2=8*Delta x#
#Delta x=120^2/16#
#Delta x=14400/16#
#Delta x=900" m"#