If an object is moving at #15 m/s# over a surface with a kinetic friction coefficient of #u_k=225 /g#, how far will the object continue to move?

1 Answer
Mar 22, 2017

Answer:

The distance is #=0.5m#

Explanation:

Kinetic friction is

#F_k=mu_k*N#

Normal reaction #=Ng#

#N=mg#

So,

#F_k=mu_k*mg#

Bu Newton's second Law

#F=ma#

#-F_k=-mu_kmg=ma#

#a=-mu_kg#

#a=-225/g*g=-225ms^2#

The negative sign indicates that this is a deceleration

Now, we apply the equation of motion

#v^2=u^2+2as#

#v=0#

#2as=-u^2=-15^2=-225#

#s=-225/-225*1/2=0.5m#