If an object is moving at #15 m/s# over a surface with a kinetic friction coefficient of #u_k=5 /g#, how far will the object continue to move?

1 Answer
May 24, 2017

Answer:

The distance is #=22.5m#

Explanation:

Let the mass of the object be #=mkg#

Then,

the coefficient of friction is

#mu_k=F_r/N#

#N=mg#

So,

#F_r=mu_k*N=5/g*mg=5m#

We apply Newton's Second Law

#F=ma=5m#

The deceleration is #=5ms^-2#

We apply the equation of motion

#v^2=u^2+2as#

#v=0#

#u=15ms^-1#

#a=-5ms^-2#

#0=15^2-2*5*s#

#s=15^2/10=22.5m#