If an object is moving at #18 m/s# over a surface with a kinetic friction coefficient of #u_k=12 /g#, how far will the object continue to move?

1 Answer
May 11, 2016

Answer:

#x=13.5 " meters"#

Explanation:

#"1- Find the friction force :"#
#F_f=u_k*m*g" "u_k=12/g#

#F_f=12/cancel(g)*m*cancel(g)#

#F_f=12m#

#"2- Find deceleration using Newton's law :"#

#F_f=m*a#

#12cancel(m)=cancel(m)*a#

#a=12 m/s^2#

#"3- Find distance using the formula :"#

#v_f^2=v_i^2-2*a*x#

#"where :"#

#v_i:"initial velocity"#
#v_f:"final velocity=0"#
#a:"deceleration"#
#x:"distance"#

#0=18^2-2*12*x#

#324=24*x#

#x=324/24#

#x=13.5 " meters"#