If an object is moving at #24 m/s# over a surface with a kinetic friction coefficient of #u_k=6 /g#, how far will the object continue to move?

1 Answer
Junaid Mirza
Nov 10, 2017

#"48 m"#

Explanation:

Kind friction (#f#) acting on object #= μ_kmg#

Retardation (a) of object #= f/m = μ_k g"#

Object will move to a distance #S#

#S = u^2 / "2a" = u^2 / (2mu_kg) = ("24 m/s")^2 / (2 × 6/cancel"g" xx cancel"g") = "48 m"#

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