Question

If an object is moving at `3 m/s` over a surface with a kinetic friction coefficient of `u_k=5 /g`, how far will the object continue to move?

Answer 1

Here KE of the object = Work done against the force of kinetic friction
So `u_kxxmxxgxxd=1/2*m*v^2`
Where `u_k= 5/g`
`m="mass",v="velocity"`
`g="acceleration due to gravity=9.8m/s^2`
`d= "distance traversed"`

`u_kxxmxxgxxd=1/2*m*v^2`
`5/gxxcancel(m)xxgxxd=1/2*cancel(m)*v^2`
`d=v^2/10=3^2/10=0.9m`