If an object is moving at #3 m/s# over a surface with a kinetic friction coefficient of #u_k=20 /g#, how far will the object continue to move?

1 Answer
May 10, 2016

Answer:

#S=0.225 m#

Explanation:

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#"First; let's calculate the friction force:"#
#F_f=u_k*G#
#G:"weight of object G=m.g"#
#u_k:" coefficient of friction"#

#F_f=u_k*m*g#

#F_f=20/g*m*g#

#F_f=20m#

#a=F_f/m#

#a=(20m)/m " "a=20 m/s^2 " acceleration of object"#

#"when object is stops ,the final velocity of its is zero"#

#v_f^2=v_i^2-2*a*S#

#v_f:"final velocity"#
#v_i:"initial velocity"#
#a:"acceleration"#
#"S:"displacement"#

#0=3^2-2*20*S#

#9=40*S#

#S=9/40#

#S=0.225 m#