If an object is moving at #5 m/s# over a surface with a kinetic friction coefficient of #u_k=3 /g#, how far will the object continue to move?

1 Answer
May 16, 2018

Answer:

The distance is #=4.17m#

Explanation:

The coeffcient of kinetic friction is #mu_k=3/g#

#mu_k=F_r/N#

Let the mass of the object be #=m kg#

Then,

The normal reaction is #N=mg N#

The frictional force is

#F_r=mu_kN=mu_kmg=3/g*mg=3mN#

According to Newton's Second Law

#F=ma#

The acceleration is #a=F/m=F_r/m=-3m/m=-3ms^-2#

The initial velocity is #u=5ms^-1#

Apply the equation of motion

#v^2=u^2+2as#

The final velocity #v=0#

#0=25-2xx3xxs#

The distance is

#s=25/6=4.17m#