If an object is moving at #6 m/s# over a surface with a kinetic friction coefficient of #u_k=3 /g#, how far will the object continue to move?

1 Answer
Feb 5, 2016

Answer:

#x=6 m#

Explanation:

#Delta E_k=1/2 .m. (v^2-0^2)#
#Delta E_k=1/2 .m. v²#
#"work doing by friction force=W"#
#W=Delta E_k#
#u_k . m. g. x=1/2 .m .v^2#
#3/cancel(g) .cancel(m) .cancel( g) . x=1/2 .cancel(m).6^2#
#6.x=36#
#x=36/6#
#x=6 m#