Question

If an object is moving at `6 m/s` over a surface with a kinetic friction coefficient of `u_k=24 /g`, how far will the object continue to move?

Answer 1

`"Object has a kinetic energy : "E_k=1/2*m*v^2`
`E_k:"The kinetic energy of object"`
`m:"mass of object"`
`v:" velocity of object"`
`"The kinetic energy of object is turned to the heat energy by "`
`"the friction force."`
`E_k=F_f*Delta x`
`1/2*cancel(m)*v^2=u_k*cancel(m)*g*Delta x`
`Delta x=v^2/(2*u_k*g)`

`Delta x=6^2/(((2*24)/cancel(g))*cancel(g))`

`Delta x=36/48`

`Delta x=3/4 " m"`