If an object is moving at #8 m/s# over a surface with a kinetic friction coefficient of #u_k=32 /g#, how far will the object continue to move?

1 Answer
May 22, 2016

Answer:

#Delta x=1 " "m#

Explanation:

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#F_f=u_k*m*g" friction force"#

#a=F_f/m=(u_k*cancel(m)*g)/cancel(m)#

#a=u_k*g#

#"given a="32/g#

#a=32/cancel(g)*cancel(g)#

#a=32 " "m/s^2#

#"its final velocity will be zero,if objects stops."#

#v_f^2=v_i^2-2*a*Delta x#

#v_f="the final velocity of object"#

#v_i="the initial velocity of object"#

#a=" acceleration"#

#Delta x=" displacement"#

#0=v_i^2-2*a*Delta x#

#v_i^2=2*a*Delta x#

#Delta x=v_i^2/(2*a)#

#Delta x=8^2/2*32#

#Delta x=1 " "m#