If an object is moving at #8 m/s# over a surface with a kinetic friction coefficient of #u_k=32 /g#, how far will the object continue to move? Physics Forces and Newton's Laws Frictional Forces 1 Answer ali ergin May 22, 2016 #Delta x=1 " "m# Explanation: #F_f=u_k*m*g" friction force"# #a=F_f/m=(u_k*cancel(m)*g)/cancel(m)# #a=u_k*g# #"given a="32/g# #a=32/cancel(g)*cancel(g)# #a=32 " "m/s^2# #"its final velocity will be zero,if objects stops."# #v_f^2=v_i^2-2*a*Delta x# #v_f="the final velocity of object"# #v_i="the initial velocity of object"# #a=" acceleration"# #Delta x=" displacement"# #0=v_i^2-2*a*Delta x# #v_i^2=2*a*Delta x# #Delta x=v_i^2/(2*a)# #Delta x=8^2/2*32# #Delta x=1 " "m# Answer link Related questions Question #d6539 Question #242b7 Question #6bde4 Question #50c79 Question #a2018 Question #f7a62 Question #27931 Question #0b375 Question #d70af Question #dab6f See all questions in Frictional Forces Impact of this question 1629 views around the world You can reuse this answer Creative Commons License