Question

If an object with a mass of `10 kg` is moving on a surface at `8 m/s` and slows to a halt after `7 s`, what is the friction coefficient of the surface?

Answer 1

initial vel = `u =8m/s`
final vel =`v=0`
retardation =`a =?`
time `t = 7s`
`0=u-axxt`
`0=8-axx7`
`a=8/7m/s^2`
Now `mumg =mxxa`
`mu =a/g=8/7xx1/9.8=0.117`