If an object with uniform acceleration (or deceleration) has a speed of $2 m/s$ at $t=0$ and moves a total of 90 m by $t=6$ , what was the object's rate of acceleration?

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Answer 1 · 2017-05-30T06:55:35

The rate of acceleration is $=4.33ms^-2$

The initial speed is $u=2ms^-1$

The distance is $s=90m$

The time is $t=6s$

The acceleration is $a=?$

We apply the equation of motion

$s=ut+1/2at^2$

Therefore,

$1/2at^2=s-ut$

$a=(s-ut)/(1/2t^2)$

$=(90-6*2)/(1/2*6^2)$

$=78/18$

$=4.33ms^-2$

If an object with uniform acceleration (or deceleration) has a speed of 2 m/s2 m/s at t=0t=0 and moves a total of 90 m by t=6t=6, what was the object's rate of acceleration?