If $g (x) = 2 x + 1$ $g(x)=2x+1$ , how do you find $g (g (x))$ $g(g(x))$ ?

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Answer 1 · 2016-12-28T00:55:23

$g (g (x)) = 4 x + 3$ $g(g(x)) = 4x + 3$

Simply input $g (x)$ $g(x)$ into $g (x)$ $g(x)$ .

$g (g (x)) = 2 (2 x + 1) + 1 = 4 x + 2 + 1 = 4 x + 3$ $g(g(x)) = 2(2x + 1) + 1 =4x + 2 +1 = 4x +3$

Hopefully this helps!

If g(x)=2x+1g(x)=2x+1g(x)=2x+1, how do you find g(g(x))g(g(x))g(g(x))?