# If gold is selling for 675 dollars an ounce, what is the value of 1.00 i n^3 of pure gold given that the density of gold is 19.3 g/(cm^3)?

Sep 1, 2016

$v a l u e = 7530.3 \mathrm{do} l l a r s$

#### Explanation:

1 in $= 2.54 c m$
1 in^3 $= 2.54 \times 2.54 \times 2.54 c {m}^{3} = 16.387 c {m}^{3}$
$16.387 \times 19.3 = 316.2691 g r a m s$
$1 o u n c e = 28.3495 g r a m s$

$\frac{316.2691}{28.3495} = 11.156 o u n c e$

$v a l u e = 11.156 \times 675 = 7530.3 \mathrm{do} l l a r s$