Question

If line allb and line A has the equation 8x-6y+9=0, determine the equation of line b, in point-slope form if b passes (1,-2)?

If line allb and line A has the equation 8x-6y+9=0, determine the equation of line b, in point-slope form if b passes (1,-2)?

Answer 1

`y=4/3*x-10/3`

Explanation:

A line parallel to `8x-6y+9=0` will be `8x-6y+c=0`.

As it passes through `(1, -2)`, putting these values in the latter

`8(1)-6(-2)+c=0` gives `c=-8-12`

i.e. `c=-20` i.e. the equation of line is

`8x-6y-20=0` or `4x-3y-10=0`

For converting it to point-slope form, one has to get the value of `y` in terms of `x`. In this equation,

`3y=4x-10` or

`y=4/3*x-10/3`

where `4/3` is slope and `-10/3` is intercept on `y` axis.