# If the area is y^2+7y, what's the base, height and perimeter of the rectangle?

Area = base * height = y² + 7y = y(y + 7)
$P e r i m e t e r = 2 \cdot \left(b a s e + h e i g h t\right) = 2 \left[y + \left(y + 7\right)\right] = 4 y + 14$