# If the density of and object is 4.0 g/cm3 and the mass is 4.0kg then how mach volume does the object occupy? Could you also show how you got there?

Feb 1, 2017

The object occupies $1000 c {m}^{3}$.

#### Explanation:

Alright so we know the formula for density is $\rho = \frac{m}{v}$
=> where $\rho$ is the density with units of the derived components, $m$ is the mass, and $v$ is the volume.

We can rearrange this formula to get us the volume.

By doing so, we get $v = \frac{m}{\rho}$. I got to this conclusion by using the "Triangle Method" - a diagram that provides an understand to how simple equations (multiply and divide) relate to one another.

I noticed that the density of the object is $4.0 \frac{g}{c {m}^{3}}$. That means that the derived components are the mass (in grams) and volume (in cubic centimetres).

Thus we have to convert the mass from $4 k g$ to grams. We can do this by multiplying the mass by $1000$. We get $4000 g$.

Now we can use the formula we rearranged and plug in the numbers to solve for the volume.

$v = \frac{m}{\rho}$

$= \frac{4000}{4}$

$= 1000$

Therefore, the volume of the space that the object occupies is $1000 c {m}^{3}$.

Hope this helps :)