If the density of coconut oil is #0.925# #g#/#cm^3#? how much does #4.25# #mL# weigh in grams?

1 Answer
anor277 · MeneerNask
Feb 24, 2016

Simply take the product #"density"xx"volume"# to give #"mass"#

Explanation:

#rho# #=# #0.925# #g*cm^-3#, #"volume"=4.25*cm^3=4.25* mL#.

#rho# #xx# #"volume"# #=# #0.925*g*cancel(cm^-3)xx4.25*cancel(cm^3)# #=# #??g#.

Note that #1*cm^3=1*mL# (because #1# #cm^3# #=# #1/10^6xxm^3-=10^-3*L#).

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