# If the density of coconut oil is 0.925 g/cm^3? how much does 4.25 mL weigh in grams?

Simply take the product $\text{density"xx"volume}$ to give $\text{mass}$
$\rho$ $=$ $0.925$ $g \cdot c {m}^{-} 3$, $\text{volume} = 4.25 \cdot c {m}^{3} = 4.25 \cdot m L$.
$\rho$ $\times$ $\text{volume}$ $=$ $0.925 \cdot g \cdot \cancel{c {m}^{-} 3} \times 4.25 \cdot \cancel{c {m}^{3}}$ $=$ ??g.
Note that $1 \cdot c {m}^{3} = 1 \cdot m L$ (because $1$ $c {m}^{3}$ $=$ $\frac{1}{10} ^ 6 \times {m}^{3} \equiv {10}^{-} 3 \cdot L$).