If the initial temperature of an ideal gas at 2.250 atm is 62.00 °C, what final temperature would cause the pressure to be reduced to 1.600 atm?

1 Answer
Nov 23, 2017

Answer:

#"238.2 Kelvin"#

Explanation:

Gay-Lussac's law: For a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

Mathematically,

#P ∝ T#

#P_f/P_i = T_f/T_i#

#T_f = T_i × P_f/P_i#

#T_f = "(62.00 + 273.15) Kelvin" × (1.600 cancel"atm")/(2.250 cancel"atm") = "238.2 Kelvin"#