# If the length of a 24 cm spring increases to 87 cm when a 5 kg weight is hanging from it, what is the spring's constant?

May 11, 2018

$\text{77.78 N/m}$

#### Explanation:

Use this equation

$\text{F = kx}$

Where

• $\text{F =}$ Force applied
• $\text{k =}$ Spring constant
• $\text{x =}$ Increase in length of spring

$\text{k" = "F"/"x" = "mg"/"x" = ("5 kg × 9.8 m/s"^2)/"0.87 m – 0.24 m" = "77.78 N/m}$