Question

If the length of a `27 cm` spring increases to `65 cm` when a `4 kg` weight is hanging from it, what is the spring's constant?

Answer 1

`103.158N//m`

Explanation:

From Hooke's Law, `F=kx`.

`therefore k=F/x`

`=((4xx9.8)N)/((0.65-0.27)m`

`=103.158N//m`