# If the length of a 27 cm spring increases to 65 cm when a 4 kg weight is hanging from it, what is the spring's constant?

Apr 24, 2016

$103.158 N / m$

#### Explanation:

From Hooke's Law, $F = k x$.

$\therefore k = \frac{F}{x}$

=((4xx9.8)N)/((0.65-0.27)m

$= 103.158 N / m$