# If the length of a 29 cm spring increases to 61 cm when a 6 kg weight is hanging from it, what is the spring's constant?

Feb 5, 2016

k = 6xx9.81/(32/100) = 6xx981/32 = 184 N/m
$\sum F = {F}_{k} - m g = k \Delta x - m g = 0$
$k = m \frac{g}{\Delta x}$
You are given m = 6kg; x_i = 29; x_f = 61#
$\Delta x = {x}_{f} - {x}_{i} = 61 - 29 = 32 c m = \frac{32}{100}$
$k = 6 \times \frac{9.81}{\frac{32}{100}} = 6 \times \frac{981}{32} = 184 \frac{N}{m}$