If the length of a #29 cm# spring increases to #61 cm# when a #6 kg# weight is hanging from it, what is the spring's constant?

1 Answer
Feb 5, 2016

Answer:

k = 6xx9.81/(32/100) = 6xx981/32 = 184 N/m#

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Explanation:

See the free body diagram on the image, at equilibrium (0 acceleration) we have :
#sumF = F_k - mg = kDeltax - mg = 0#
# k = mg/(Deltax) #
You are given #m = 6kg; x_i = 29; x_f = 61#
#Deltax = x_f - x_i = 61 - 29 = 32 cm = 32/100#
#k = 6xx9.81/(32/100) = 6xx981/32 = 184 N/m#