If the length of a #63 cm# spring increases to #98 cm# when a #15 kg# weight is hanging from it, what is the spring's constant?
1 Answer
May 14, 2018
Explanation:
We use Hooke's law, which states that,
where:
#F# is the force exerted on the spring in newtons
#k# is the spring constant, usually in newtons per meter
#x# is the extension of the spring in meters
Here:
#F=15 \ "kg"*9.8 \ "m/s"^2=147 \ "N"#
#x=(98 \ "cm"-63 \ "cm")*(1 \ "m")/(100 \ "cm")=0.35 \ "m"#