# If the mass of an object is 4 kg while its volume is 20 m^3, what would its density be?

May 18, 2017

$0.2 \frac{k g}{{m}^{3}}$
or
$2 \times {10}^{- 4} \frac{g}{c {m}^{3}}$

#### Explanation:

The equation for density:

$\rho = \frac{m}{V}$

Plug in known values, if your answer is in units of $\frac{k g}{{m}^{3}}$:

$\rho = \frac{4 k g}{20 {m}^{3}} = 0.2 \frac{k g}{{m}^{3}}$

A more conventional unit for density is $\frac{g}{c {m}^{3}}$. The conversion to this is:

$0.2 \frac{k g}{{m}^{3}} \left(\frac{{10}^{3} g}{1 k g}\right) \left(\frac{1 {m}^{3}}{{100}^{3} c {m}^{3}}\right) = 2 \times {10}^{- 4} \frac{g}{c {m}^{3}}$