# If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C , what would the new pressure be?

May 1, 2014

Pressure and Temperature have a direct relationship as determined by Gay-Lussac Law

$\frac{P}{T} = \frac{P}{T}$

Pressure and temperature will both increase or decrease simultaneously as long as the volume is held constant.

Therefore if temperature were to increase the pressure would likewise increase. Increased temperature would increase the energy of the molecules and the number of collisions would therefor increase causing an increase in temperature.

${P}_{1}$ = 5.00 atom
${T}_{1}$ = 20 C + 273 = 293 K
${P}_{2}$ = x atm
${V}_{2}$ = 40 C + 273 = 313 K

$\frac{5.00 a t m}{293 K} = \frac{P}{313 K}$

$\frac{1565 a t m K}{293 K} = P$

P = 5.34 atm

Increasing the temperature, likewise increased the pressure.