# If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to the pressure of the gas?

May 1, 2014

Doubling the temperature, likewise doubled the pressure.

#### Explanation:

Pressure and Temperature have a direct relationship as determined by Gay-Lussac Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

Pressure and temperature will both increase or decrease simultaneously as long as the volume is held constant.

If temperature were to double the pressure would likewise double. Increased temperature would increase the energy of the molecules and the number of collisions would also increase causing the increase in pressure.

Take a sample of gas at STP 1 atm and 273 K and double the temperature.

$\frac{1 a t m}{273 K} = {P}_{2} / \left(546 K\right)$

$\frac{2 \cancel{546 K} a t m}{\cancel{273} \cancel{K}} = {P}_{2}$

${P}_{2} = 2 a t m$

Doubling the temperature likewise doubled the pressure.