# If the sum of three consecutive integers is 147, what are the integers?

Jan 25, 2017

$48 , 49 , 50$

#### Explanation:

Consider that the numbers are in an arithmetic sequence, where $a$ is the first term and $d$ is the common difference

In this case, the common difference is $1$

$a + a + d + a + 2 d = 147$

$3 a + 3 d = 147$

$3 a = 144$

$a = 48$

So numbers are $48 , 49 , 50$