If the sum of three consecutive odd integers is 129, what are the integers?

2 Answers
Feb 3, 2016

Answer:

#41, 43, and 45#

Explanation:

Let the smallest of the three consecutive odd numbers be #n#

Then the three odd numbers will be: #n, n+2, n+4#

We are told
#color(white)("XXX")n+(n+2)+(n+4)=129#

#rarrcolor(white)("XXX")3n+6=129#

#rarrcolor(white)("XXX")3n=123#

#rarrcolor(white)("XXX")n=41#

and the three consecutive odd numbers are #41, (41+2), (41+4)#

Feb 3, 2016

Let the first number be #omega#
The difference of consecutive odd numbers is #2#
So,the next two numbers are #omega+2# , #omega+4#

Then,

#rarr(omega) +(omega+2)+(omega+4)=129#

Remove brackets:

#rarromega +omega+2+omega+4=129#

#rarr3omega+6=129#

#rarr3omega=129-6#

#rarr3omega=123#

#rarromega=123/3=41#

So,#omega+2=41+2=43 , omega+4=41+4=45#

The three integers are #41,43 and 45#