# If the sum of three numbers is 138. the second is 5 more than the smallest and the third is 10 more than the smallest how do you find the numbers?

Sep 3, 2015

I found: $41 , 46 , 51$

#### Explanation:

Call the smallest $x$ so you get:
$x + \left(x + 5\right) + \left(x + 10\right) = 138$
$3 x + 15 = 138$
$3 x = 123$
$x = 41$
so you get:
$41 , 46 , 51$