In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 mL of HCl to completely neutralize the acid?

1 Answer
May 16, 2017

Answer:

Well, you need to add #45.0*mL# of your standard #NaOH# solution precisely...........

Explanation:

And first we represent the reaction by an equation:

#HCl(aq) + NaOH(aq) rarr NaCl(aq) + H_2O(l)#

And thus there is #1:1# #"stoichiometry"#.

We use the relationship #"Molarity"="Moles of solute"/"Volume of solution"#.

What is the volume of the solution at equivalence?