# In meters, the diagonals of two squares measure 10 and 20, respectively. How do you find the ratio of the area of the smaller square to the area of the larger square?

If side length of square is 'a' then length of diagonal is $\sqrt{2}$a.
So ratio of the diagonals is equal to the ratio of the sides which is equal to $\frac{1}{2}$.
Also area of square is ${a}^{2}$. So ratio of area is ${\left(\frac{1}{2}\right)}^{2}$ which is equal to $\frac{1}{4}$.