# In the (x, y) coordinate plane, what is the radius of the circle described by the equation #(x - 3)^2 + (y + 6)^2=sqrt15#?

##### 1 Answer

Aug 15, 2016

The given equation is the equation of a circle with center at

#### Explanation:

It is apparent from the equation's LHS that the square of distance of the point

Hence, the given equation is the equation of a circle with center at