# In triangle ABC, sin A=1/3, sin B=1/5, and b=6, how do you find side a?

##### 1 Answer

Apr 25, 2015

Use the trig identity: a/sin A = b/sin B

a = b.(sin A/sin B) = 6. (5/3) = 10.

Apr 25, 2015

Use the trig identity: a/sin A = b/sin B

a = b.(sin A/sin B) = 6. (5/3) = 10.

2871 views
around the world

You can reuse this answer

Creative Commons License

Creative Commons License