# In Triangle NOP, how do you express p^2 in terms of n, o, and cosP?

By the Law of Cosine, ${p}^{2} = {n}^{2} + {o}^{2} - 2 n o \cos P .$
By the Law of Cosine, ${p}^{2} = {n}^{2} + {o}^{2} - 2 n o \cos P .$